(6/(y^2-9y+8))-(1/(y-8))=1/(4y-4)

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Solution for (6/(y^2-9y+8))-(1/(y-8))=1/(4y-4) equation: 



(6/(y^2-9y+8))-(1/(y-8))=1/(4y-4)

We move all terms to the left:

(6/(y^2-9y+8))-(1/(y-8))-(1/(4y-4))=0



Domain of the equation: (y^2-9y+8))!=0

y∈R





Domain of the equation: (y-8))!=0

y∈R





Domain of the equation: (4y-4))!=0

y∈R



We calculate fractions


((6*(y-8))*4y)/((y^2-9y+8))*(y-8))*(4y-4)))+(-(1*(y^2-9y+8))*4y)/((y^2-9y+8))*(y-8))*(4y-4)))+(-(1*(y^2-9y+8))*y)/((y^2-9y+8))*(y-8))*(4y-4)))=0

We can not solve this equation

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